Question

A ball is kicked at 30 degrees above the horizontal from a cliff of a height of 100 m with a speed v i= 40 m/s. How far from the base of the cliff will the ball hit the ground?

Answer 1

Given:

The angle is

`\theta\text{ = 30}^(\circ)`

The speed of ball is v = 40 m/s

To find the range.

Step-by-step explanation:

The range of the ball can be calculated as

`\begin{gathered} R=(v^2sin(2\theta))/(g) \\ =\text{ }((40)^2sin(2*30))/(9.8) \\ =141.39\text{ m} \end{gathered}`

Thus, the range is 141.39 m