Question

Identify the asymptote(s) of this function: y=5/(x-4)+1

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Answer 1

`y= (5)/((x-4)+1)`

`y= (5)/(x-3)`
So you take the denominator and compare to zero.

`x-4+1=0`

`x-3=0`

`x=3`
Then the horizontal asymptote is y = 0