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Sujith S · Answer 1 · 2018-12-08T22:24:54+0000

Answer: D)
$_(94)^(239)\textrm{Pu}$

Explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of alpha decay :

$_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)Y+_2^4{He}$

Thus
$_(94)^(239)\textrm{Pu}\rightarrow _(94-2)^(239-4)Y+_2^4{He}$

$_(94)^(239)\textrm{Pu}\rightarrow _(92)^(235)U+_2^4{He}$

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