Question

A game has a rectangular board with an area of 44in2. There is a square hole near the top of the game board in which you must not toss in a bean bag. The square has side lengths of 3in. What is the probability of tossing the bag through the hole?

Answer 1

9/44 chance of tossing it through the hole.

Answer 2

Answer: Probability of tossing the bag through the hole =
`(9)/(44)`

Explanation:

Since we have given that

A game has a rectangular board with an area of 44 in².

There is a square hole near the top of the game board in which you must not toss in a bean bag.

Length of Side of a square = 3 in.

So, Area of square of square is given by

`Area=Side* Side\\\\=3* 3\\\\=9\ in^2`

So, Probability of tossing the bag through the hole will be

`\frac{\text{Number of favourable outcome}}{\text{ Total number of outcomes }}\\\\=(9)/(44)`

Hence, Probability of tossing the bag through the hole =
`(9)/(44)`