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Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water

1 Answer

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M = GFM × N

Sodium Oxide

s Na O
v 1 2
s 2 1
d 2 1
f Na2O

Na2O

2 × 23 = 46
1 × 16 = 16
46 + 16 = 62g

GFM = 62g
N = 2.24 moles
M = ?

M = GFM × N
M = 62,2 × 2.24
M = 138.88g
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