Question

Suppose that the sample size had been 4500 rather than 1033. Find the margin of error for 95% confidence for the larger sample Give your answer to three decimal places. margin of error:

Answer 1

The formula for calculating margin of error is expressed as

`\text{margin of error = z }*\text{ (}\sqrt[]{(pq)/(n)})`

Where

p represents the probability of success

q represents the probability of failure

n represents sample size

z represents the z score for a 95% confidence interval

From the information given,

p = 30% = 30/100 = 0.3

q = 1 - p = 1 - 0.3 = 0.7

n = 4500

From the standard normal distribution table, z = 1.96

By substituting these values into the formula, we have

`\text{margin of error = 1.96}*\sqrt[]{(0.3*0.7)/(4500)}\text{ = }0.013`

margin of error = 0.013