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How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with 1.15 liters of a 2.75 molar potassium chromate K2CrO4 solution? Pb(NO3)2
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How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with 1.15 liters of a 2.75 molar potassium chromate K2CrO4 solution? Pb(NO3)2 + K2CrO4 PbCrO4 + 2KNO3 108 g 681 g 639 g 362

User Rasean
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I know that the answer is 639 g
User ICreative
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