Question

What is the area of this triangle?

a) a=1/2(y3-y2)(x3-x1)
B) a=1/2(y3-y1)(x3-x1)
C) a=1/2(y2-y1)(x3-x1)

Answer 1

D. A =
`(1)/(2) (y_(2) -y_(1) )(x_(3) -x_(1) )`

Explanation:

This was correct on plato:)

Answer 2

The area of a triangle is:

A=hb/2 where h=height and b=base

We can let the "height" be the horizontal magnitude, (x3-x1)

And the base would then be the vertical magnitude, (y2-y1)

So the area is:

A=(1/2)(y2-y1)(x3-x1)