Question

A die-cast plane toy is scaled at inch to 1 foot. If the toy is 6.5 inches wide and 8.5 inches long, determine the dimensions of the actual plane, to the nearest foot.

What is the:
Width:
length:

Answer 1

Using the scale of 1 inch to 1 foot, the actual dimensions of the plane are 6.5 feet wide and 8.5 feet long.

Step-by-step explanation:

To determine the actual dimensions of the plane, we first establish that the scale is 1 inch to 1 foot. We will then use this scale to convert the dimensions of the die-cast plane toy to the actual plane. For the width, which is 6.5 inches on the toy, we use the formula:

Actual width (in feet) = Scale * Width on toy (in inches)

Actual width (in feet) = 1 foot/inch * 6.5 inches = 6.5 feet

Similarly, we can calculate the length of the actual plane using the given length of the toy, which is 8.5 inches:

Actual length (in feet) = Scale * Length on toy (in inches)

Actual length (in feet) = 1 foot/inch * 8.5 inches = 8.5 feet

Therefore, the dimensions of the actual plane, rounded to the nearest foot, are 7 feet in width and 8.5 feet in length.

Answer 2

Given that the die-cast plane is scaled at 1 inch to 1 foot. This means that for each foot of the actual plane, the toy is 1 inch.

Therefore, the dimensions of the actual plane is given by 1 x 6.5 inches wide by 1 x 8.5 inches long = 6.5 inches wide by 8.5 inches long.