Question

Two boys are throwing a baseball back and forth. The ball is 4 ft above the ground when it leaves one child’s hand with an upward velocity of 36 ft/s. If acceleration due to gravity is –16 ft/s2, how high above the ground is the ball 2 s after it is thrown?

Answer 1

the answer is a 12ft

Answer 2

The ball is about
`44 ft\\` above the ground

Explanation:

As per newton's second law of motion

`S = ut + (1)/(2) at^2\\`

Substituting the given values in above equation, we get -

`S = (36)(2) + (1)/(2) (-16)(2^2)\\= 40 ft\\`

The total height including the height of ball from where it is throws

`40 ft  + 4 ft\\= 44 ft\\`