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How many pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix worth $1.50 per pound?

a. 9
b. 20
c. 114.5

User Sabina
by
7.7k points

2 Answers

7 votes
the answer is 9 pounds.
User Aakash Thakur
by
8.6k points
1 vote

Answer:

9 pounds

Explanation:

Let the amount of nuts be x

Cost of 1 pound nuts is $1.10

So, Cost of x pounds = $1.10 x

Cost of 1 pound of candy = $ 1.60

Cost of 36 pounds of candy =
1.60 * 36=57.6

So, total cost = 1.10 x + 57.6

Total weight = x+36

Cost of mixture per pound =
\frac{\text{total cost}}{\text{total weight}}

Now we are given that Cost of mixture per pound is $1.50

So,
(1.1x+57.6)/(x+36)=1.50


1.1x+57.6=1.50(x+36)


1.1x+57.6=1.50x+54


57.6-54=1.50x-1.1x


3.6=0.4x


(3.6)/(0.4)=x


9=x

Hence 9 pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix worth $1.50 per pound.

User Max Bublikoff
by
8.0k points