Question

Az+17=−4z−b

Solve for Z

*this is a linear equation btw

Answer 1

we have

`Az+17=-4z-b`

Adds the term
`4z` both sides

`Az+17+4z=-4z-b+4z`

`Az+17+4z=-b`

Subtract the term
`17` both sides

`Az+17+4z-17=-b-17`

`Az+4z=-b-17`

`z(A+4)=-(b+17)`

Divide both sides by
`(A+4)`

`z=-(b+17)/(A+4)`

therefore

the answer is

`z=-(b+17)/(A+4)`