Question

The manager of a baseball team has 15 players to choose from for his 9 person batting order

Answer 1

The answer is 1,816,214,400 not 5005. Just took the quiz

Explanation:

Answer 2

Given the question:
The manager of a baseball team has 15 players to choose from for his 9-person batting order. How many different ways can he arrange the players in the lineup?
5,005 362,880 3,603,600 1,816,214,400

The number of was in which a smaller group is choosing from a bigger group is given by the bigger number combination the smaller number.

`^nC_r= (n!)/((n-r)!r!)`
Here, we want to choose a 9-person batting order from a team of 15 players. This is given by:

`^(15)C_9= (15!)/((15-9)!9!)=(15*14*13*12*11*10*9!)/(6!*9!)= (3,603,600)/(720) =5,005`