Figure ABCD has vertices A(−2, 3), B(4, 3), C(4, −2), and D(−2, 0). What is the area of figure ABCD?

Question

asked Nov 15, 2018 115k views

1 Answer

SlashmanX · Answer 1 · 2018-11-18T17:19:07+0000

The area of figure ABCD is:

24 square units.

We see that the given points form the vertices of a trapezium ABCD with bases AD and CB with measure,

AD= 3 units

and CB=5 units

and the height of the trapezium is: AB= 6 units.

Hence, the area of trapezium ABCD is:

$Area=(1)/(2)* (AD+CB)* AB\\\\\\Area=(1)/(2)* (3+5)* 6\\\\\\Area=(1)/(2)* 8* 6\\\\\\Area=24$

Hence, the area of figure ABCD is:

24 square units.