Question

Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).

(4, -4)
(2, -2)
(1, -4)

Answer 1

We know that when
`A=(x_A,y_A)` and
`B=(x_B,y_B)` the midpoint of the line segment AB is given by:


`M=\left((x_A+x_B)/(2),(y_A+y_B)/(2)\right)`

Here
`A=(-2,5)` and
`B=(6,-9)` so:


`M=\left((x_A+x_B)/(2),(y_A+y_B)/(2)\right)=\left((-2+6)/(2),(5+(-9))/(2)\right)=\\\\\\=\left((4)/(2),(5-9)/(2)\right)=\left(2,(-4)/(2)\right)=\boxed{\left(2,-2\right)}`