Solution:
Given:
Rearranging the data,
![\begin{gathered} 8,35,36,39,41,42 \\ \\ The\text{ mean is;} \\ mean=(8+35+36+39+41+42)/(6) \\ mean=(201)/(6) \\ mean=33.5 \\ \\ \\ The\text{ median is;} \\ Median=(36+39)/(2) \\ Median=(75)/(2)=37.5 \\ \\ \\ The\text{ data has no mode because no other data has repeated values or appears more than the other} \end{gathered}]()
From the data given, the data has an outlier and the outlier makes the data skewed.
As the data becomes skewed, the mean loses its ability to provide the best central location for the data because the skewed data is dragging it away from the typical value.
However, the median is not as strongly influenced by the skewed values.
Therefore, for the data given, the median is the only appropriate measure of center.