Given
Rope at second harmoic frequency is 8hz
Procedure
The fundamental vibrational mode of a stretched string is such that the wavelength is twice the length of the string.
f1 = Fundamental frequency
f2 = 2f1
f1 = f2/2
f1 = 8 Hz/2
f1 = 4 Hz
Now, for the fifth harmonic
f5 = 32f1
f5 = 32*4
f5 = 128 Hz
The fifth harmonic would be 128 hz