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The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probability that the 2 does not end up face down?
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The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probability that the 2 does not end up face down?

User Kavya Mugali
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2 Answers

1 vote

Answer:

long answer short, its 3/4

User Ifeanyi Echeruo
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3 votes
probablity=desrierdoutcomes/totalposssibleotcomes

totalpossible=numberofsides=4

desired is NOT 2
there are 1,2,3,4
the ones that are NOT 2 are 1,3,4
those are 3 sides

so probablity that it isn't 2, is 3/4 or 75%
User Dmitry Kurmanov
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