Question

A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle, then write a ratio of the circle’s circumference to the perimeter of the square.

Answer 1

for squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2


find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches

areanotcovered=676-530.66=145.34 square inches not coverd


ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785

Answer 2

area of square = s^2 = (26)^2

area of circle = pi*r^2 = 3.14*(13)^2

area of square not covered by the circle = 26^2-3.14(13)^2

perimeter of square = 4s = 4(26) = 104

circumference of circle = pi*d = 3.14*26

circumference:perimeter ratio => 3.14:4