Question

Susan has a jar of jellybeans. She has 10 yellow, 5 green, 3 red, and 2 black jellybeans. What is the probability thatshe will get a yellow jellybean on her first grab, replace it, and then grab a black jellybean on her second grab?Write your answer in simplest form.оO 20O 30о3

Answer 1

The probability formula is given by:

`\text{ P(E) =}\frac{\text{ N(Required outcome)}}{\text{ N(Total outcome)}}`

Number of yellow jellybeans, n(Y) = 10

Number of green jellybeans, n(G) = 5

Number of red jellybeans, n(R) = 3

Number of black jellybeans, n(B) = 2

Total number of balls = 10 + 5 + 3 + 2 = 20 balls

P( she gets a yellow jellybean first, replaces it, and grabs a black jellybean)

`\begin{gathered} \text{ P(gets a yellow jellybean) =}(10)/(20) \\ \text{ P(grabs a black jellybean) =}(2)/(20) \end{gathered}`
`\text{ P( yellow first, black second with replacement) =}(10)/(20)*(2)/(20)\text{ =}(1)/(20)`

Therefore, the answer to the probability that susan gets a yellow jellybean on her first grab, replaces it, and grabs a black jellybean is 1/20