Question

What is the product?


`(2a-7)/(a)* (3a^2)/(2a^2-11a+14)`

A.
`(3)/(a-2)`
B.
`(3a)/(a-2)`
C.
`(3a)/(a+2)`
D.
`(3)/(a+2)`

Answer 1

B. 3a/a-2
im taking it

Answer 2

The denominator of the second fraction can be factored as (a-2)(2a-7), then it becomes doable. You cancel the (2a-7) factors, and are left with:


`(3a^2)/(a(a-2)) \implies (3a)/(a-2)`

Do note that you have erased the fact that a≠0 and a≠7/2, so you should always mention that.