Question

The equation shows the combustion of butane (c4h10. how many moles of water can be produced by 12.5 moles of c4h10 with excess oxygen?

Answer 1

The combustion reaction for this would be written as:

C4H10 + 13/2O2 = 4CO2 + 5H2O

We are given the amount of butane to be used in the reaction. This will be the starting point for our calculation. We also use the balanced reaction to relate the substances.

12.5 mol C4H10 ( 5 mol H2O / 1 mol C4H10 ) = 62.5 mol H2O produced