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If sin y° = 9 divided by c and tan y° = 9 divided by d, what is the value of cos y°?

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7 votes
siny=9/c

tany=9/d


we know that tany =siny/cosy==> 9/d=(9/c)/cosy

cosy=9d/c divided by 9 , that means multiply by 1/9

so cosy d/c
User Rob Kent
by
8.1k points
2 votes

Answer:

value of
\cos y^(\circ) is
(d)/(c)

Explanation:

Given :
\sin y^(\circ)=(9)/(c) \\\\ \tan y^(\circ)=(9)/(d)

we have to find the value of
\cos y^(\circ)

Using trigonometric relation between tangent , sine and cosine we have,


\tan \theta=(\sin \theta)/(\cos \theta)

We are given


\sin y^(\circ)=(9)/(c) \\\\ \tan y^(\circ)=(9)/(d)

Substitute, in relation above, we have


\tan y^(\circ) =(\sin y^(\circ))/(\cos y^(\circ))


(9)/(d)=((9)/(c) )/(\cos y^(\circ))

solve for
\cos y^(\circ) , we have


\cos y^(\circ)=(9)/(c)* (d)/(9)

Simplify , we get


\cos y^(\circ)=(d)/(c)

Thus, value of
\cos y^(\circ) is
(d)/(c)

User Siraj Ul Haq
by
7.7k points

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