Question

a clothing store sells t-shirts, t, for $8 a shirt, shorts, s, for $12, and hats, h, for $10 each. The store earned $464 revenue last month. The store sold three times as many T-shirts than hats, and twice as many shorts as hats. Using the substitution method, how many t-shirts, shorts, and hats did the store sell?

Answer 1

t=15;s=5

Explanation:

Answer 2

Let x be the variable for a t-shirt for $8.
Let y be the variable for shorts for $12.
Let z be the variable for the hats that cost $10 each.


We have the expression 1 below:
$464 = $8x + $12y + $10z
other expressions:
3z = x
2z =y

By substitution we can solve each variable:

464 = 8(3z) + 12(2z) + 10z
464 = 24z +24z +10z
464 = 58z
z = 8

Solve for x andy:
3z=x
3*8 = 24=x
2z=y
2*8 = 16 = y

The t-shirts are 24 pieces, the shorts are 16 pieces and hats are 8 pieces.