Question

Solve square root
X^2+12x+43=0

Answer 1

x²+12x+43=0

This a quadratic equation ax²+bx+c=0 (in our case a=1, b=12, & c=43)

to solve it, means to calculate the value of x which render this equation nil

In short we have to find the roots x' & x'' by applying the following formula:

x' = [-b+√(b² - 4ac)] / 2a & x" =[-b - √(b² - 4ac)] / 2a
If you plug the related values you will notice the amount inside the radical (√)
is negative. As you know such an amount should be positif, hence their is no roots & consequently no solution

Answer 2

`x^2+12x+43=0`


`x= (-b+ √(b^2-4ac) )/(2a), (-b- √(b^2-4ac) )/(2a)`


`x= (-12+ √(12^2-4*43) )/(2)`,
`(-12- √(12^2-4*43) )/(2)`


`x= (-12+2 √(7i) )/(2), (-12-2 √(7i) )/(2)`


`x=-6+ √(7i),-6- √(7i)`