Question

At Jefferson High School, a student takes 4 core classes a day. There are 6 different core classes offered. How many different combinations of classes are there? 12 combinations 15 combinations 24 combinations 10 combinations

Answer 1

Order does not matter so you would want to use the "n choose k" equation:

n!/(k!(n-k)!), where n=number of possible choices and k=number of selections

In this case:

6!/(4!(6-4)!)

6!/(4!*2!)

15

So there are 15 unique combinations of classes possible.