At how many points does the graph of the function below intersect the x-axis? y = 2x^2 - 7x + 7

Question

asked Jul 17, 2018 65.4k views

2 Answers

Bodrov · Answer 1 · 2018-07-24T17:39:22+0000

Answer:

0

No such point on graph.

Explanation:

Given:
y=2x^2-7x+7

We are given quadratic equation. We need to find number of points where it cuts x-axis.

When graph cuts x-axis their y-value is 0

We will set the equation to 0 and solve for x

2x^2-7x+7=0

Using quadratic formula.

$x=(-b\pm√(b^2-4ac))/(2a)$

where, a=2 , b=-7 , c=7

$x=(7\pm√(49-56))/(2(2))$

$x=(7\pm √(-7))/(4)$

$x=(7\pm i√(7))/(4)$

The value of x is imaginary. So, y will not cut x-axis any any point.

Hence, No such point on graph which cut x-axis.