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Question 2

so hmmm those are the vertices, check the picture below

thus

$\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ -3}}\quad ,&{{ 7}})\quad % (c,d) B&({{ -6}}\quad ,&{{ -1}})\\ B&({{ -6}}\quad ,&{{ -1}})\quad % (c,d) C&({{ 9}}\quad ,&{{ -1}})\\ C&({{ 9}}\quad ,&{{ -1}})\quad % (c,d) A&({{ -3}}\quad ,&{{ 7}})\\ \end{array}\ % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\ -----------------------------\\\\$

$\bf AB=√([-6-(-3)]^2+[-1-7]^2)\implies AB=√(9+64) \\\\\\ \boxed{AB=√(73)} \\\\\\ BC=√([9-(-6)]^2+[-1-(-1)]^2)\implies BC=√(225) \\\\\\ \boxed{BC=15} \\\\\\ CA=√([9-(-3)]^2+[-1-7]^2)\implies CA=√(144+64) \\\\\\ \boxed{CA=4√(13)}$

thus, the perimeter of △ABC is AB + BC + CA

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