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Convert the complex number 2 - 2 (sqrt 3) i into its polar representation.

User CMerrill
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2 Answers

6 votes
4(cos(300)+isin(300))
User Saurabh Hirani
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8.3k points
1 vote
Answer: 4 <-60

A complex number in rectangular form is Z, where Z = a + bi.
In the given above 2-2(sqrt 3)i. In order to change it into polar form ( z= r (cos theta + i sin theta) ) or r < theta, we have to find r first.

r = |z| = sqrt ( a^2 + b^2)
= sqrt (2^2 + (-2 sqrt 3)^2)
= 4
then theta = arctan(b/a)
= arctan ((-2sqrt3)/2)
= -60 degrees
Polar form = 4 ( cos (-60) + i sin (-60))
= 4 < -60 degrees
User Averasko
by
7.5k points

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