Register
Jason's age is 3 times Shauna's present age. In 4 years time,the sum of their ages will be 56 years. Find their present ages.
119k views
4 votes
Jason's age is 3 times Shauna's present age. In 4 years time,the sum of their ages will be 56 years. Find their present ages.

User Lee Harrison
by
6.5k points

1 Answer

5 votes
Let s and 3s be Shauna's age and Jason's age, respectively. Then:
s+4+3s+4=56
4s=48
s=12
Shauna is 12; Jason is 36. ☺☺☺☺
User JustRaman
by
7.2k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.8m questions

10.5m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!