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What is the quotient?


(n+3)/(2n-6) * (n+3)/(3n-9)

A. 2/3
B. 3/2
C.
((n+3)^2)/(6(n-3)^2)
D.
(6(n-3)^2)/((n+3)^3)

User Yozhik
by
8.2k points

2 Answers

5 votes

Answer is c on e2020

User RoR
by
8.3k points
2 votes
To get the answer to this problem you first factor out the common term 2

(n+3)/(2(n-3) ) * (n+3)/(3n-9)

then factor out the common term 3

(n+3)/(2 (n-3) ) * (n+3)/(3 (n-3) )

then simplify

( (n+3)(n+3)/(2 (n-3)*3(n-3) )

Use product rule : x^a x^b= x^a+b

( (n+3)^2/(2 (n-3)*3(n-3) )

simplify 2 (n-3) * 3(n-3) to 6(n-3)(n-3)

( (n+3)^2/(6 (n-3)(n-3) )

use product rule again : x^a x^b=x^a+b

so you get the answer : ( (n+3)^2)/(6 (n-3)^2 )

so the orrect answer to this problem is answer choice (C)
User Sorenkrabbe
by
9.1k points

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