147k views
0 votes
The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm? The iron has a mass of 213 g. Remember that water has a density of 1.00 g/cm3. Hint: Determine the volume of the displaced water. Then determine the mass using your knowledge of the density of water. Finally, convert the mass to weight using Weight = mg, where mass is in kilograms and gravity, g = 9.80 m/s2.

27.0 g
2.76 g
265 N
0.265 N

2 Answers

1 vote

Answer:

0.265 N

Step-by-step explanation:

User Bar Nuri
by
8.0k points
1 vote
The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g. Remember that water has a density of 1.00 g/cm3.

To determine the weight of the displaced water, we need to know the volume of the block. Since the entire block is submerged, the volume of displaced water = volume of block!!

Volume of block = 3 * 3 * 3 = 27 cubic cm
Now we need to determine the weight of 27 cc of water.
Weight = mass in kg * 9.8

Density = mass / volume
1 g/cc = mass / 27
Mass = 27 g

Weight = mass in kg * 9.8
Mass in kg = 0.027 kg
Weight of block = 0.027 * 9.8 = 0.2646 N

The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object.

Buoyant force = 0.2646 N
a is incorrect, because force is weight, not mass
d is correct,
User Johan Karlsson
by
8.7k points