Question

It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°

c. The specific heat of the substance is 1.2 J/g°
c. What is the mass?

Answer 1

the answer is 15g, you would use the specific heat formaula

Answer 2

`m=14.6g`

Step-by-step explanation:

You can use the equation
`Q=cm(T_(2)-T_(1))` where Q is the heat, c is the specific heat of the substance,
`T_(2)` and
`T_(1)` are temperature and m is the mass of the substance.

Solving for m we have:

`m=(Q)/(c(T_(2)-T_(1)))`

The problem gives you the information about the variables:

`Q=350J`

`c=1.2(J)/(g^(o)C)`

`T_(1)=10.0^(o)C`

`T_(2)=30.0^(o)C`

Replacing that values:

`m=(350J)/(1.2(J)/(g^(o)C)(30.0^(o)C-10.0^(o)C))`

`m=(350J)/(1.2(J)/(g^(o)C)(20.0^(o)C))`

`m=14.6g`