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In ∆IJK, i= 340 cm < I =120° and

User Joseph Argenio
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1 Answer

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Find K

K/sin 1 = 340/sin120

k = 340 sin 1 / sin120

K = 340 *(0.020)

K = 6.85 cm

Find J

J/sin 59 = 340/sin120

J = 340 sin59/sin120

J = 340 *(0.98977)

J = 336.5 cm

Area = base x height / 2

height = 6.85

Area = 6.85 x 336.5 / 2

Area = 2305.025 / 2

Area = 1152.5 cm^2

In ∆IJK, i= 340 cm < I =120° and-example-1
User Sanderfish
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