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Answer question from quadratic graph f(x) = -x + 6 -x^2

Answer question from quadratic graph f(x) = -x + 6 -x^2-example-1
User Dalmas
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1 Answer

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20 votes

Answer

When x = -1.5, y = 5.25

When y = 5, x = -1.62 and 0.62

(i) (-0.5, 6.25)

(ii) x = -0.5

Step-by-step explanation

From the graph:

When x = -1.5, y = 5.25 (Traced on the graph with red color)

When y = 5, x = -1.62 and 0.62 (Traced on the graph with blue color)

(i) The coordinates of the maximum turning point on the graph is: (-0.5, 6.25) (Traced on the graph with green color).

(ii) To use the formula = -b/2a to justify the x-value at the turning point, we use:


\begin{gathered} f(x)=-x+6-x^2 \\ \text{from the function,} \\ a=-1,b=-1,\text{ and c }=6 \\ x=(-b)/(2a)=(-\mleft(-1\mright))/(2*(-1))=(1)/(-2)=(-1)/(2)=-0.5 \end{gathered}

The turning point is justified.

Answer question from quadratic graph f(x) = -x + 6 -x^2-example-1
User Thykof
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2.8k points