Question

A juggler has a bag containing three yellow balls, five green balls, four blue balls, and one red ball, all the same size. The juggler pulls a ball from the bag at random. Then, without replacing it, he pulls out a second ball. What is the probability that the juggler first draws a green ball followed by a blue ball?

Answer 1

3 yellow + 5 green + 4 blue + 1 red = 13 total

Probability green:
`(5 Green)/(13 Total)`
Probability blue:
`(4 Blue)/(12 Total)`

Probability green then blue:
`(5 Green)/(13 Total)` x
`(4 Blue)/(12 Total)` =
`(20)/(156) = (5)/(39)`