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What is the difference (x/x^2+3x+2)-(1/(x+2)(x+1)

a. (x-1)/(6x+4)
b. (-1)/4x+2)
c. (1)/(x+2)
d. (x-1)/x^2+3x+2)

User Emili
by
7.6k points

2 Answers

4 votes

Answer:

Option D is correct

The difference of
(x)/(x^2+3x+2)- (1)/((x+2)(x+1)) =
(x-1)/(x^2+3x+2)

Explanation:

To find the difference of the equation:


(x)/(x^2+3x+2)- (1)/((x+2)(x+1)) ....[1]

first multiply the terms


(x+2)(x+1) =(x^2+x+2x+2)

Substitute this in equation [1], we have


(x)/(x^2+3x+2)- (1)/(x^2+3x+2)

If the denominators are same, then we have


(x+(-1))/(x^2+3x+2) =
(x-1)/(x^2+3x+2)

Therefore, the difference of the given equation
(x)/(x^2+3x+2)- (1)/((x+2)(x+1)) is,
(x-1)/(x^2+3x+2)




User Seb Bizeul
by
8.2k points
0 votes
answer is D i believe
User Maksym Bykovskyy
by
7.3k points

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