Question

The difference between 3 times a number and another number is 15. The sum of 4 times the first number and the second number is 13. find the numbers

Answer 1

Ur answear is in the pic

Answer 2

Let x be the first number and y be the second number, since the difference between 3 times x and y is 15, and the sum of 4 times x and y is 13, we can set the following system of equations:

`\begin{gathered} 3x-y=15, \\ 4x+y=13. \end{gathered}`

Adding both equations we get:

`3x-y+4x+y=15+13.`

Simplifying the above equation we get:

`7x=28.`

Dividing the above equation by 7 we get:

`\begin{gathered} (7x)/(7)=(28)/(7), \\ x=4. \end{gathered}`

Now, substituting x=4 in 4x+y=13 we get:

`\begin{gathered} 4\cdot4+y=13, \\ 16+y=13. \end{gathered}`

Subtracting 16 from the above equation we get:

`\begin{gathered} 16+y-16=13-16, \\ y=-3. \end{gathered}`

Answer: The first number is 4 and the second is -3.