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If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?
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If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?

User Raghavendra Bankapur
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1 Answer

4 votes
The area of the cross-section is 169 sq. cm.

That is the correct answer to this problem
User Ssb
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