Question

Two pools are being filled. To start, the first pool contains 890 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.25 liters per minute. Water is being added to the second pool at a rate of 42.5 liters per minute.

Answer 1

first pool = 890 lts rate = 20.25 lts/min

second pool = empty rate = 42.5 lts

1.- rate = volume / time

time = volume/rate

Equation

890 + 20.25t = 42.5t

Solve for t (time)

890 = 42.5t - 20.25t

890 = 22.25t

t = 890/22.25

t = 40 min

2.-

Tank 1 Volume = 890 + 20.25(40)

Volume = 890 + 810

Volume = 1700 lts

Tank 2 Volume = 42.5(40)

= 1700 lts