The national average SAT score is 1028. Assume a normal distribution with standard deviation being 92. What is the 99th percentile score?

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asked Feb 7, 2018 165k views

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Zircon · Answer 1 · 2018-02-11T05:24:15+0000

Similar to your other question. Now, you're looking for the score

such that

$\mathbb P(X\le k)=0.99$

This time, 0.99 corresponds to a z-score of approximately
$\hat k=2.3264$ , which means

$(k-1028)/(92)=\hat k\implies k\approx92(2.3264)+1028=1242.03\approx1242$

The national average SAT score is 1028. Assume a normal distribution with standard deviation being 92. What is the 99th percentile score?

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