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What is the sum of the geometric series E^4 i=1^6^i-1 A. 43 B. 259 C. 1259 D. 1554

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Answer:

259 is the correct answer

User Plicatibu
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\displaystyle\sum_(i=1)^46^(i-1)=1+6+6^2+6^3

\displaystyle6\sum_(i=1)^46^(i-1)=6+6^2+6^3+6^4

\implies\displaystyle\sum_(i=1)^46^(i-1)-6\sum_(i=1)^46^(i-1)=1-6^4

\implies\displaystyle-5\sum_(i=1)^46^(i-1)=1-6^4

\implies\displaystyle\sum_(i=1)^46^(i-1)=\frac{6^4-1}5=259
User Dean Elbaz
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