Question

Factor completely. 9x^4 -225y^8

Answer 1

This is of the form: (a^2-b^2) called a difference of squares, which means each term is a perfect square. Differences of squares always factor to:

(a+b)(a-b) in this case:

(3x^2+15y^4)(3x^2-15y^4) which if we factor out the 3s is

3(x^2+5y^4)*3(x^2-5y^4)

9(x^2+5y^4)(x^2-5y^4) and this cannot be factored any further unless we use imaginary numbers ±i√5

9(x^2+5y^4)(x-(i√5)y^2)(x+(i√5)y^2)

Answer 2

The answer is 9x^4 - 225y^8 = 9(x^2+5y^4)(x^2 - 5y^4)
Answer: 9(x^2+5y^4)(x^2-5y^4)


Hope this helps ya! :]