Question

What would P(A|B) be?

Answer 1

`P(A \cap B) = P(A) \cdot P(B)`

so


`P(A) = (P(A \cap B))/(P(B)) = (2/3)/(3/4) = (8)/(9)`

also, if A or B happens but not both, you add the chances and subtract the chance that both are happening.


`P(A|B) = P(A) + P(B) - P(A \cap B) = (8)/(9) +(3)/(4) - (2)/(3) = (35)/(36)`