Question

Question 4 please explain in detailed

Answer 1

v = 2.0 m/s
m = 15,000kg
g = 1.6 N/kg

A) F = ma / F = mg
F = (15,000kg)(1.6 N/kg) = 24,000N
So the upward force of 24,000 balances out the downward force of 24,000. There is no net force and therefore, no acceleration. This allows for a constant velocity.

B) F = ma
Net force: 24,000 - 25,000 = -1,000
-1,000 = (15,000kg)a
a = -.067
`(m)/(s^(2) )`

t = 18.0s




`v_(f) ^(2) = v_(i) ^(2) + at`

`v_(f)^(2) = (2.0 (m)/(s)) ^(2) + (-.067 (m)/( s^(2) ))(18.0s)`

So the final velocity is 1.67 m/s