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What is the axis of symmetry of h(x) = 6x2 − 60x + 147?
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What is the axis of symmetry of h(x) = 6x2 − 60x + 147?

User Roman Yakoviv
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2 Answers

3 votes
hello :
h(x) = 6x² − 60x + 147= (x² -2(30)x+30²)-30²+147
h(x) = (x-30)²-753 .....(vertex form)
the axis of symmetry is the line of equation : x=30
User Syed Umer Hasan
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5 votes

The answer is x=5 and d on edgen





User Jbmilgrom
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