Question

Sydney Runs at 5m/s grabs a rope at the ground, how high does he swing?

Answer 1

Given:

The speed of Sydney is,

`v=5\text{ m/s}`

let the maximum height she reaches is h.

From the conservation of energy, we can write,

`\begin{gathered} (1)/(2)mv^2=mgh \\ h=(v^2)/(2g) \end{gathered}`

Substituting the values we get,

`\begin{gathered} h=(5*5)/(9.8) \\ =2.55\text{ m} \end{gathered}`

Hence, the maximum height is 2.55 m.