Factor completely 9x^4y − 6x^3y^2 + 3x^2y^3. A-3x^2y(3x^2 − 2xy + y^2 B-3xy(3x^2 − 2xy + y^2 C-3xy^2(3x^2 − 2xy + y^2 D-3x^2y(3x^2 + 2xy + y^2

asked Nov 1, 2018 198k views

5 votes

Factor completely 9x^4y − 6x^3y^2 + 3x^2y^3.

A-3x^2y(3x^2 − 2xy + y^2
B-3xy(3x^2 − 2xy + y^2
C-3xy^2(3x^2 − 2xy + y^2
D-3x^2y(3x^2 + 2xy + y^2

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The answer is A because if you factor out 3x^2y, you get 3x^2 - 2xy + y^2 and you cannot factor that out anymore

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