Solution
Part 1
For this case we can do the following:
E(x)= -25*0.90 + 175*0.06+ 275*0.04= -1.00
Part 2
For this case we can do the following:
E(x)= -5*0.76 + 0*0.12+ 5*0.06+ 15*0.03+ 45*0.02+ 95*0.009+ 495*0.001= -0.80
Part 3
For this case in both games the expected value is negative but the one on which is most probable to loss less is on Game 2