Question

A rectangular pyramid has a base measuring 4 in. on each side and an altitude of 6 in. What is its volume? cubic inches

Answer 1

the answer is 32.
you use the formula (1/3) b^2 h.
so you would have 4^2 which is 16. 16x6= 96.
96x.33= 31.68
round up its 32

Answer 2

`V=512in^3`

Explanation:

A rectangular pyramid is a polyhedron whose surface is formed by a base that is a rectangle and triangular side faces that converge on a vertex called the apex. The volume of a rectangular pyramid is given by:

`V=(1)/(3) *b^2*h`

Where:

`b=Area\hspace{3}of\hspace{3}the\hspace{3}base\\h=Pyramid\hspace{3}height`

The problem tell us that on each side the base has a length of 4 in, therefore, the area of the base is:

`b=4*4=16in`

The problem also tell us that:

`h=6in`

So, replacing the previous data in the volume equation:

`V=(1)/(3) *(16)^(2)*6=(256*6)/(3)  =(1536)/(3) =512in^3`